Sum of probabilities of getting an even number and an odd number when a die is rolled is
A) 1/2
B) 1/6
C) 1/3
D) 1
Correct option is (D) 1
Possible outcomes when a die is rolled are S = {1, 2, 3, 4, 5, 6}.
\(\therefore\) Total outcomes is n(S) = 6
E = Event of getting an even number = {2, 4, 6}
0 = Event of getting an odd number = {1, 3, 5}
\(\therefore\) n(E) = 3 & n(0) = 3
\(\therefore\) P(E) \(=\frac{n(E)}{n(S)}=\frac36=\frac12\) and
P(0) \(=\frac{n(0)}{n(S)}=\frac36=\frac12\)
\(\because\) P(E) + P(0) \(=\frac12+\frac12\) = 1
Hence, the sum of probabilities of getting an even number and an odd number when a die is rolled is 1.