Sum of probabilities of getting an even number and an odd number when a die is rolled is
A) 1/2
B) 1/6
C) 1/3
D) 1
Correct Answer - `(i) 5/18 (ii) 1/12 (iii) 5/12`
2 Answers 1 viewsCorrect Answer - `(i) 1/12 (ii) 1/4 (iii) 1/12 (iv) 5/18 (v) 1/6`
2 Answers 1 viewsCorrect option is (D) Odd number Sum of three odd numbers is odd. Sum of an odd number and an even number is odd. \(\therefore\) Sum of three odd numbers and one even number is odd.
2 Answers 1 viewsCorrect option is (D) impossible Possible outcome when a die is thrown are 1, 2, 3, 4, 5 and 6. Hence, favourable outcome of event of getting a number more than 6...
2 Answers 1 viewsCorrect option is (C) 1 When an unbiased coin is tossed then possible outcomes are S = {H, T}. \(\therefore\) P(H) = \(\frac12\) & P(T) \(=\frac12\) \(\therefore\) P(H) + P(T) \(=\frac12+\frac12=1\) Hence, sum of probabilities of getting a head...
2 Answers 1 viewsCorrect option is (D) 1 Possible outcomes when a die is rolled are S = {1, 2, 3, 4, 5, 6}. \(\therefore\) Total outcomes is n(S) = 6 E = Event of getting an even...
2 Answers 1 viewsC) Both (i) & (iv)
2 Answers 1 views(1) f(x) = \(\frac{x}{1-x^3}\) f(-x) = \(\frac{-x}{1-(-x)^3}\) = \(\frac{-x}{1+x^3}\) ≠ -f(x) or f(x) ∴ f(x) is neither even nor odd function. (2) f(x) = \(\frac{x^2}{1+x}\) ∴ f(-x) = \(\frac{(-x^2)}{1+(-x)}\) = \(\frac{x^2}{1-x}\) ≠ -f(x) or f(x). (3) f(x) = x-|x| ∴ f(-x) = -x-|-x| = -x-|x| = -(x+|x|) ≠ -f(x)...
2 Answers 1 views