Sum of the probabilities of getting a head and a tail when an unbiased coin is tossed is
A) 1/2
B) 1/4
C) 1
D) 0
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A die is thrown. Find the probability of (i) getting a 5 (ii) getting a 2 or a 3 (iii) getting an odd number (iv) getting a prime number (v) getting a
Correct Answer - `(i) 1/6 (ii) 1/3 (iii) 1/2 (iv) 1/2 (v) 1/3 (vi) 1/3`
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In a single throw of two dice, find the probability of (i) getting a sum less than 6 (ii) getting a doublet of odd numbers (iii) getting the sum as a
Correct Answer - `(i) 5/18 (ii) 1/12 (iii) 5/12`
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Three unbiased coins are tossed once. Find the probability of getting (i) exactly 2 tails (ii) exactly one tail (iii) at most 2 tails (iv) at least 2
Correct Answer - `(i) 3/8 (ii) 3/8 (iii) 7/8 (iv) 1/2 (v) 7/8`
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A coin is tossed 500 times and we get heads : 285 times and tails : 215 times When a coin is tossed at random , what is probability of getting (i) a h
Correct Answer - (i) 0.57 (ii) 0.43
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Two coins are tossed 400 times and we get two heads : 112 times, one head , 160 times , 0 head , 128 times . When two coins are tossed at random , wha
Correct Answer - (i) 0.28 (ii) 0.4 (iii) 0.32
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Getting a ‘head’ when an unbiased coin is tossed is …………………
Correct option is (B) equally likely When an unbiased coin is tossed then Probability of getting head is P(H) \(=\frac12\) and Probability of getting tail is P(T) \(=\frac12.\) Hence, getting a head when an unbiased coin is tossed...
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Getting a ‘head’ when an unbiased coin is tossed is …………………
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The probability of getting a head when a coin is tossed is
Correct option is (C) 1/2 When a coin is tossed, possible outcomes are head and tail. S = {H, T} Total outcomes is n(S) = 2 Number of favourable outcomes of event of getting...
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The probability of getting a head when a coin is tossed is
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Sum of the probabilities of getting a head and a tail when an unbiased coin is tossed is
Correct option is (C) 1 When an unbiased coin is tossed then possible outcomes are S = {H, T}. \(\therefore\) P(H) = \(\frac12\) & P(T) \(=\frac12\) \(\therefore\) P(H) + P(T) \(=\frac12+\frac12=1\) Hence, sum of probabilities of getting a head...
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