Correct option is (C) 1/2
When a coin is tossed, possible outcomes are head and tail.
S = {H, T}
Total outcomes is n(S) = 2
Number of favourable outcomes of event of getting a head is n(E) = 1.
\(\therefore\) Probability of getting a head is P(E) \(=\frac{n(E)}{n(S)}=\frac12.\)