A die is thrown. Find the probability of
(i) getting a 5 (ii) getting a 2 or a 3
(iii) getting an odd number (iv) getting a prime number
(v) getting a multiple of 3 (vi) getting a number between 3 and 6
Correct Answer - B
`(b)` Let `A` be the event of drawing a black ball.
`A_(1)`, the event of choosing the first box.
`A_(2)`, the event of choosing the second box....
Correct Answer - C
`(c )` `E:` Event of getting on outcome `(n_(1), n_(2),n_(3))` such that `i^(n_(1))+i^(n_(2))+i^(n_(3))=1`
`E_(1) : ` Event that fair die is thrown
`E_(2) :` Event that biased...
Correct option is (D) impossible
Possible outcome when a die is thrown are 1, 2, 3, 4, 5 and 6.
Hence, favourable outcome of event of getting a number more than 6...
Correct option is (D) 1
Possible outcomes when a die is rolled are S = {1, 2, 3, 4, 5, 6}.
\(\therefore\) Total outcomes is n(S) = 6
E = Event of getting an even...