If √3 = 1.732, then \(\sqrt{27}\) = ....................
A) 3 x 1.732
B) 9 x 1.732
C) 27 x 1.732
D) 6 x 1.732
Correct Answer - `-0.891`
2 Answers 1 viewsFocal length of spherical mirrors are independent of the medium.
2 Answers 2 viewst18=t1+17×d t14=t1 +13×d solving the two equtaions, t18-t14= 4d subtisting 4d=32 = d=8
2 Answers 1 viewsCorrect option is (A) 3 x 1.732 \(\sqrt{27}=\sqrt{3^3}=\sqrt{3^2\times3}\) \(=\sqrt{3^2}\times3=3\times\sqrt3\) = \(3\times1.732\)
2 Answers 1 viewsCorrect option is (A) ΔABC ≅ ΔDEF In \(\triangle ABC\;and\;\triangle EFD,\) AB = EF (Both hypotenuse are equal) \(\angle C=\angle D\) \(=90^\circ\) (Angles opposite to hypotenuse) AC = ED (Given) \(\therefore\) \(\triangle ABC\cong\triangle EFD\) ...
2 Answers 1 views12011 + 22011 + 32011 +...... +20102011 = (12011 + 20102011) + (22011 + 20092011) + (32011 + 20082011) ...... (10112011 + 10002011) These terms are of the form an + bn, so they will be divided by a + b, as n...
2 Answers 1 viewsCorrect option is (D) ₹ 680 Let cost price of radio be Rs x. \(\therefore\) Selling price = x + 10% of x = x + \(\frac{10x}{100}\) = x + \(\frac{x}{10}\) \(=\frac{11x}{10}.\) Given that selling price = Rs 748 \(\therefore\) \(\frac{11x}{10}=748\) \(\Rightarrow\) \(x=\frac{748}{11}\times10=680\) \(\therefore\) Cost price...
2 Answers 1 viewsCorrect option is (D) 3 Distance covered by car by travelling 60 kmph in 4 hours = speed \(\times\) time \(=60\times4\) = 240 km When car travels at 80 kmph then time by the car \(=\frac{Distance}{Speed}\) \(=\frac{240}{80}\) =...
2 Answers 1 views