If √3 = 1.732, then \(\sqrt{27}\) = ....................
A) 3 x 1.732
B) 9 x 1.732
C) 27 x 1.732
D) 6 x 1.732
2 Answers
Talk Doctor Online in Bissoy App
Talk Doctor Online in Bissoy App
Given `sqrt(2)=1.414, sqrt(3)=1.732, sqrt(5)=2.236`, find the value, correct to three decimals of the following `(1-sqrt(3))/(sqrt(5)-sqrt(2))`
Correct Answer - `-0.891`
2 Answers 1 views
If a convex mirror is held in air and then dipped in oil, then what will be the change in its focal length?
Focal length of spherical mirrors are independent of the medium.
2 Answers 2 views
Find the common difference of an A.P if \( t_{18}-t_{14}=3 L \). If \( 3+k, 18-k, 5 k+1 \) are in A.P, then find \( k \). If \( p \) and \( q \) are positive integers, then we write \( p=a^{2} b^{3} \) and \( q=a^{3} b \) if \( a \), \( b \) are numbers, then verify that L.C.M of \( (p, q) \times \) H.C.F of \( (p, q)=p q \).
t18=t1+17×d t14=t1 +13×d solving the two equtaions, t18-t14= 4d subtisting 4d=32 = d=8
2 Answers 1 views
If √3 = 1.732, then √27 = ....................
2 Answers
1 views
In Two right angle triangles their hypotenuse AB, EF are equal and AC = DE then then which of the following is not true?
Correct option is (A) ΔABC ≅ ΔDEF In \(\triangle ABC\;and\;\triangle EFD,\) AB = EF (Both hypotenuse are equal) \(\angle C=\angle D\) \(=90^\circ\) (Angles opposite to hypotenuse) AC = ED (Given) \(\therefore\) \(\triangle ABC\cong\triangle EFD\) ...
2 Answers 1 views
In Two right angle triangles their hypotenuse AB, EF are equal and AC = DE then then which of the following is not true?
2 Answers
1 views
If n is odd, then an + bn is divisible by (a + b) and an− bn is divisible by (a − b). If n is even, then an− bn is divisible by (a − b) and (a + b) .
12011 + 22011 + 32011 +...... +20102011 = (12011 + 20102011) + (22011 + 20092011) + (32011 + 20082011) ...... (10112011 + 10002011) These terms are of the form an + bn, so they will be divided by a + b, as n...
2 Answers 1 views
One person sold a radio at 10% profit then he gets Rs. 748 then the C.P of that radio was …………………..
Correct option is (D) ₹ 680 Let cost price of radio be Rs x. \(\therefore\) Selling price = x + 10% of x = x + \(\frac{10x}{100}\) = x + \(\frac{x}{10}\) \(=\frac{11x}{10}.\) Given that selling price = Rs 748 \(\therefore\) \(\frac{11x}{10}=748\) \(\Rightarrow\) \(x=\frac{748}{11}\times10=680\) \(\therefore\) Cost price...
2 Answers 1 views
One person sold a radio at 10% profit then he gets Rs. 748 then the C.P of that radio was …………………..
2 Answers
1 views
If a car travels 60 kmph then it reaches the destination in 4 hours. If the car travels at 80 kmph then the time taken by car is ………………. hrs
Correct option is (D) 3 Distance covered by car by travelling 60 kmph in 4 hours = speed \(\times\) time \(=60\times4\) = 240 km When car travels at 80 kmph then time by the car \(=\frac{Distance}{Speed}\) \(=\frac{240}{80}\) =...
2 Answers 1 views