Calculate the energy released in kilowatt-hours when 100g of `._(3)^(7)Li` are converted into `._(2)^(4)He` by proton bombardment. Mass of `._(3)^(7)Li = 7.0183 am u`, mass of proton = 1.0081 amu. Write down the nuclear reaction.


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Correct Answer - `._(3)^(7)Li + ._(1)^(1)H` (proton) `rarr 2 ._(2)^(4)He + Q` (energy released), 6.554 xx 10^(6) kWh`

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