Calculate the energy released in kilowatt-hours when 100g of `._(3)^(7)Li` are converted into `._(2)^(4)He` by proton bombardment. Mass of `._(3)^(7)Li = 7.0183 am u`, mass of proton = 1.0081 amu. Write down the nuclear reaction.
Answered Feb 05, 2023
Correct Answer - `._(3)^(7)Li + ._(1)^(1)H` (proton) `rarr 2 ._(2)^(4)He + Q` (energy released), 6.554 xx 10^(6) kWh`
Correct Answer - 2.2 MeV
Correct Answer - `9 xx 10^(14)` J
Correct Answer - `2.36 xx 10^(13)` J
Correct Answer - [(a) 4.25 MeV; (b) 23 MeV]
Correct Answer - `[5.7 xx 10^(8) J]`
Correct Answer - `[9 xx 10^(14), 2.25 xx 10^(5) "ton"]`
Correct Answer - 39.3 MeV
Correct Answer - `5.1 xx 10^(23) MeV`
Correct Answer - `6x + 11y le 200`
Correct option is D) Mosley
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