(i) 50 amu `" "` (ii) 50 gm
(iii) `because` 50 gm of element contains `6.022xx10^(23)` atoms
`therefore ` 10 gm of element will contain `(6.022xx10^(23))/(50)xx10=1.2044xx10^(22)` atoms
(iv) `because 6.022xx10^(23)`...
(i) mass of 1 molecules =75 amu
`therefore` mass of 100 molecules=7500 amu
(ii) Mass of 5000 molecules =`5000xx75` amu
`=5000xx75xx1.67xx10^(-24)=6.26 25xx10^(-19)` gm
`because 6.022xx10^(20)` molecules weights `(75)/(6.022xx10^(23))xx6.022xx10^(20)=0.075` gm
(iv)...
Correct Answer - A, C
More the nucleons, more the more the binding energy & more reduced is the mas. So, `M_(2) lt 20(m_(p)+m_(n))` (Because some mass got reduced on release...
