Calculate the Q - value of the reaction
`._(1)H^(2)+._(1)H^(2) rarr ._(1)H^(3)+._(1)H^(1)`
`m(._(1)H^(2))=2.014103 "amu" m(._(1)H^(3))=3.016049 "amu" m(._(1H^(1))=1.007825` amu
(i) 50 amu `" "` (ii) 50 gm (iii) `because` 50 gm of element contains `6.022xx10^(23)` atoms `therefore ` 10 gm of element will contain `(6.022xx10^(23))/(50)xx10=1.2044xx10^(22)` atoms (iv) `because 6.022xx10^(23)`...
2 Answers 1 views(i) mass of 1 molecules =75 amu `therefore` mass of 100 molecules=7500 amu (ii) Mass of 5000 molecules =`5000xx75` amu `=5000xx75xx1.67xx10^(-24)=6.26 25xx10^(-19)` gm `because 6.022xx10^(20)` molecules weights `(75)/(6.022xx10^(23))xx6.022xx10^(20)=0.075` gm (iv)...
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2 Answers 1 views