And `alpha`-particle with kinetic enregy `T_(alpha) = 7.0 MEV` is scattered elastically by an initially stationary `.^(6)Li` nucleus. Find the kinetic energy of the recoil nucleus if the angle of divergence of the two particles is `theta = 60^(@)`. Take masses of `alpha` partice and lithium as m and M respectively.
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An `alpha`-particle having kinetic energy x MeV falls on a Cu-foil. The shortest distance from the nucleus of Cu to which `alpha`-particle reaches is
Correct Answer - 5 `K.E.=(KZe.2e)/(r ), " "K.E.=(9xx10^(9)xx29xx2(1.6 xx 10^(-19))^(2))/(1.67xx10^(-14))=5Mev`
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If `A(alpha, beta)=[("cos" alpha,sin alpha,0),(-sin alpha,cos alpha,0),(0,0,e^(beta))]`, then `A(alpha, beta)^(-1)` is equal to
Correct Answer - A We have, `A(alpha, beta)^(-1)=1/e^(beta) [(e^(beta) cos alpha,-e^(beta) sin alpha,0),(e^(beta) sin alpha,e^(beta) cos alpha,0),(0,0,1)]` `=A(-alpha, -beta)`
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(a) Why is an alpha particle, rather than neutrons and protons, emitted from an unstable nucleus? (b) A nucleus `.^(A)X` alpha decays to produce Y. Th
Correct Answer - (b) A=228
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The `alpha`-decay of nucleus `X^(230)` is accompanied by emission of two groups of `alpha-`particles-one group having `alpha-`particles of kinetic ene
Correct Answer - 1.53MeV
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A protom of energy 1 MeV is incident head-on on a gold nucleus (Z = 79), and is scattered through an angle of `180^(@)`. Calculate the distance of nea
Correct Answer - `11.37 xx 10^(-4) m`
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What is the distance of closest approach to the nucleus for an `alpha`-particle of energy 5J MeV which undergoes scattering in the Gieger-Marsden expe
Correct Answer - `4.13 xx 10^(-14) m`
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An alpha particles kinetic energy `T= 5.3 MeV` initiates a nuclear reaction `Be^(9)(alpha,n)C^(12)` with energy yield `Q=+5.7MeV`. Find the kinetic en
Correct Answer - `[T_(n) = (Q + (1 -m_(a)//m_(c))T)/(1 + m_(n)//m_(c)) = 8.5 MeV]`
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A stationary `._(82)^(200)Pb` nucleus emits an `alpha`-particle with kinetic energy `T_(alpha) = 5.77 MeV`. Find the recoil velocity of a daughter nuc
Correct Answer - `[3.4 xx 10^(5) m//s, 0.020]`
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Find the energy of the reaction `.^(14)N(alpha, p) .^(17)O`, if the kinetic energy of the incoming `alpha`-particle is `T_(alpha) = 4.0 MeV` & the pro
Correct Answer - `[Q = (1-eta_(p))T_(p) - (1-eta_(alpha))T_(alpha)-2 sqrt(eta_(p)eta_(alpha)T_(p)T_(alpha)) cos theta =-12 MeV, "where" n_(p) = m_(p)//m_(o), n_(alpha) = (m_(alpha))/(m_(0))]`
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Find the greatest possible angle through which a deuteron is scattered as result of elastic collision with an initially stationary proton ? Take `m_(1
Correct Answer - `[beta_(max) = sin^(-1).(m_(1))/(m_(2)) = 30^(@)]`
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