Find the greatest possible angle through which a deuteron is scattered as result of elastic collision with an initially stationary proton ? Take `m_(1)` & `m_(2)` as masses of a proton & a deuterium.
Correct Answer - `x gt (n)/(n+2)` and `x lt (n+2)/(n)`
If n is even, the greatest coefficient is `.^(n)c_(n//2)`. Therefore, the greatest term is `.^(n)C_(n//2)x^(n//2)`.
`:. .^(n)C_(n//2)x^(n//2)gt.^(n)C_((n//2)-1)x^((n-2)//2)` and `.^(n)C_(n//2)x^(n//2) gt .^(n)C_((n//2)+1)x^((n//2)+1)`...
Correct Option is (B) 2h
Greast vertical height is h
Maximum Height \(v = \sqrt {2gh}\)
Maximum Range \(R = \frac{u^2 sin \ 2 \ \theta}{g}\)
\(R = \frac{u^2 }{g} sin \ 2 \ \theta\)
\(\because v =...
No.
Elastic Collision
Inelastic Collision
i.
In an elastic collision, both momentum and kinetic energy are conserved.
In an inelastic collision, momentum is conserved but kinetic energy is not conserved.
ii.
The total kinetic energy after collision...