The greatest height to which a man can throw a stone is h. The greatest distance to which he can throw it will be
(A) h/2
(B) 2h
(C) h
(D) 3h
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Correct Option is (B) 2h
Greast vertical height is h
Maximum Height \(v = \sqrt {2gh}\)
Maximum Range \(R = \frac{u^2 sin \ 2 \ \theta}{g}\)
\(R = \frac{u^2 }{g} sin \ 2 \ \theta\)
\(\because v = \sqrt{2gh}\)
Correct Option is (B)
Maximum distance covered when \(\theta = 45^\circ\)
\(R = \frac{u^2}{g} sin 90^\circ\)
\(R = \frac{(\sqrt{2gh})}{g}\)
\(R = \frac{2gh}{g}\)
\(R = 2h\)
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