(a) Why is an alpha particle, rather than neutrons and protons, emitted from an unstable nucleus? (b) A nucleus `.^(A)X` alpha decays to produce Y. The vol- ume of nucleus Y is nearly 56 times the volume of alpha particle. Find the mass number (A) of X.
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If a variable takes the discrete values `alpha-4`, `alpha -(7)/(2), alpha-(5)/(2), alpha-2,alpha+(1)/(2), alpha-(1)/(2), alpha+5(alpha gt 0)`, then th
Correct Answer - A Arrange the data as follows : `alpha-(7)/(2), alpha-3, alpha-(5)/(2),alpha-2, alpha-(1)/(2),alpha+(1)/(2),alpha+4,alpha+5` Median `=(1)/(2)` [value of 4th item+value of 5th item] `therefore " Median"=(alpha-2+alpha-(1)/(2))/(2)=(2alpha-(5)/(2))/(2)=alpha-(5)/(4)`
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A radioactive nucleus decays by emitting one alpha and two beta particles, the daughter nucleus is ….. Of the parent.
Correct Answer - isotope
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A sample contains two isotopes -one stale and the other unstable. Number of stable nuclei is equal to `N_(s)` and number of unstable nuclei is equal t
Correct Answer - `N_(s)//N_(u)=1//3`
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In the thorium decay series that begins with `.^(232)Th,.^(228)Th` alpha-decays into `.^(224)Ra` with a half life of 1.9yr. `.^(224)Ra` alpha-decays i
Correct Answer - 5.9kg,1149kg
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A radioactive nucleus A decay to C after emitting two `alpha` and three `beta` particles. Another nucleus B decays to C by emitting one `alpha` and fi
Correct Answer - (a) `Z_(A)-Z_(B)=4;A_(A)-A_(B)=4` (b) `(9N_(0))/(2)` (c) 6 hr
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A nucleus at rest decays by emitting at `alpha` particle. The de-Broglie wavelenght of emitted `alpha` particle is `lambda=-5.76` femtometer. Mass of
Correct Answer - 227.62u
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A radioactive sample consists of two isotopes one of then decays by `alpha-` emission with a half life of `tau_(1)=405s` and the other one decays by `
Correct Answer - (a) `(1)/(9)` (b) 1215s
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A radioactive nucleus A decays into B with a decay constnat `lambda_(1)`. B is alos radioactive and it decays into C with a decay constant of `lambda_
Correct Answer - (a)`(dN_(2))/(dt)=-lambda_(2)N_(2)+lambda_(1)N_(1)^(0)e^(-lambda_(1)t)` (b) `(A_(2))/(A_(1))=(lambda_(2))/(lambda_(2)-lambda_(1))` (c) `((1)/(lambda_(2)-lambda_(1)))ln((lambda_(2))/(lambda_(1)))`
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Suppose a nucleus initally at rest undergoes `alpha` decay according to equation `._(92)^(225)X rarr Y +alpha` At `t=0`, the emitted `alpha`-particles
Correct Answer - `[(a) ((q_(alpha)E_(0))/m_(alpha)t)i+v_(0) cos theta hat(j)-v_(0) sin theta hat(k)` where `theta=omegat` and `omega=(q_(alpha)B)/m_(alpha)`, (b) `10^(7) m//s` (c) `8.00 MeV]`
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The nucleus `._(92)^(235)U` decays according to `._(92)^(238)U rarr ._(92)^(234)Th + ._(2)^(4)He`. Calculate the kinetic energy of the emitted `alpha`
Correct Answer - `8.8 xx 10^(-13)J`
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