An electron approaches a fixed proton from a large distance with a kinetic energy of 12.2 eV. The electron gets captured by the proton to form a hydrogen atom in an excited state and a photon of wavelength `lambda_(1) = 796 Å` is emitted. Later, the hydrogen atom de-excites by emitting a single photon of wavelength `lambda_(2)`. Find `lambda_(2)`. [Take `h = 6.62 xx 10^(– 34) Js, c = 3 xx 108 m//s`]
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A particle performs SHM of amplitude A along a straight line. When it is at distance `sqrt(3)/2` A from mean position, its kinetic energy gets increas
Correct Answer - C at `x = (sqrt(3))/(2)A` `KE = 1/2 momega^(2) (A^(2) - (3)/(4)A^(2)) = 1/8 momega^(2)A^(2)` `KE` is increased by an amount of `1/2momega^(2)A^(2)`. Let now amplitude be `A_(1)`...
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An electron collides with a dfixed hydrogen atom in its ground stat. Hydrogen atom gets excited and the collding electron loses all its kinetic energy
Correct Answer - 2 Kinetic energy of electron `= 13.6 [1-1/9] eV = 12.1 eV`.
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An electron with initial kinetic energy of `100 eV` is acclerated through a potential difference of `50 V`. Now the de-Brogile wavelength of electron
Correct Answer - A For electron `lambda_(db)=sqrt(150/(100+50))=1 Å`
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An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom gets excited and the colliding electron loses all its kinetic energ
Correct Answer - C Excitation upto `n=3` is required so that visible length is emitted upon de-excitation. So required energy `=13.6 (1-1/9)=12.1 eV`
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A negatively charged muon (mass 207 times the mass of an electron) is captured in a Bohr’s orbit of high principal quantum number (n). The atom thus f
Correct Answer - (b) `z = 48`
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Assume that an electron and a position pair is formed from a gamma ray photon having energy 3.0 MeV. Find the total kinetic energy of the positron and
Correct Answer - 1.98MeV.
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Calculate the electric potential energy of an electron-proton system of an atom . The radius of the orbit of the electron is `21.16xx10^(-11)`m the ch
Correct Answer - `-1.088xx10^(-18)J`
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A photon of energy 12.09 eV is absorbed by an electron in ground state of a hydrogen atoms. What will be the energy level of electron ? The energy of
Correct Answer - n=3
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At what temperature the average value of the kinetic energy of the molecule of a gas will be `1//3` of the average value of kinetic energy at `27^(@)C
Correct Answer - `-173 ^(@)C`
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An alpha particles kinetic energy `T= 5.3 MeV` initiates a nuclear reaction `Be^(9)(alpha,n)C^(12)` with energy yield `Q=+5.7MeV`. Find the kinetic en
Correct Answer - `[T_(n) = (Q + (1 -m_(a)//m_(c))T)/(1 + m_(n)//m_(c)) = 8.5 MeV]`
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