Calculate the electric potential energy of an electron-proton system of an atom . The radius of the orbit of the electron is `21.16xx10^(-11)`m the charge on electron is `1.6xx10^(-19)C`.
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The de Broglie wavelength of an electron moving in a circular orbit is `lambda` . The minimum radius of orbit is :
Correct Answer - B We know `2 pir=nlambda` For minimum radius `n=1` `2pir_("min")=lambda` `r_("min")=lambda/(2pi)`
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Deduce the condition when the De-Broglie wavelength associated with an electron would be equal to that associated with a proton if a proton is `1836`
Correct Answer - `v_(e)=1836 v_(p)` Debroglie wavelength associated with particle of mass `(m)` moving with velocity `(v)` is `lambda=h/(mv) rArr lambda_(P)=h/(m_(P)v_(P))` and `lambda_(e)=h/(m_(e)v_(e))` given `lambda_(p)=lambda_(e) rArr (h)/(m_(p)v_(p))=h/(m_(e)v_(e)) rArr m_(p)v_(p)=m_(e)v_(e)` `v_(e)/v_(p)=m_(p)/m_(e)=1836 rArr...
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If velocity of an electron in `I` orbit of `H` atom is `V`, what will be the velocity of electron in `3^(rd)` orbit of `Li^(2+)`
Correct Answer - A `V=2.188xx10^(6) Z/n m//s` Now, `V prop Z/n` so, `V_(Li^(2+))/V_(H)=-(Z_(1)//n_(1))/(Z_(2)//n_(2))=(3//3)/(1//1)=1` or, `V_(Li^(2+))=V_(H)`
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The orbit having Bohr radius equal to 1st Bohr orbit of H-atom is :
Correct Answer - D `r_(n)=0.529 n^(2)/Z ` For hydrogen, `n=1` and `Z=1, :. r_(H)=0.529` For `Be^(3+), n=2` and `Z=4, :. r_(Be^(3+))=(0.529xx2^(2))/(4)=0.529` there, (D) is correct option.
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A system of positron `(+1^(e^(0)))` and electron `(–1^(e^(0)))` is called Positronium atom. The radii of Positronium atom is expanded but energy level
Correct Answer - (a) `2` , (b) yes
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A proton X is projected in a region of uniform electric field E with speed u. Another proton Y is projected simultaneously with same speed u in a sepa
Correct Answer - (a) `(pi)/(2) + sin^(-1) ((sigmaET)/(2u))` , (b) `sqrt(u^(2) - (sigma^(2)E^(2)T^(2))/(4)) .T`
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An electron approaches a fixed proton from a large distance with a kinetic energy of 12.2 eV. The electron gets captured by the proton to form a hydro
Correct Answer - `1217 Å`
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ABCD is a square of side 4 cm. Charges of `16xx10^(-9) C, -16xx10^(-9) C` and `32xx10^(-9)C` are placed at the points A, C and D, respectively. Determ
Correct Answer - `9sqrt3xx 10 ^(4) NC^(-1)`," inclined at an angle of"`9^(@) 44 ` "with AB produced"
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By giving energy to a hydrogen atom in energy state n=1. If the potential energy of the atom in n=1 state be `-13.6 eV`, calculate (a) potential enreg
Correct Answer - `-0.85 eV, 12.75 eV, 971 Å`
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Calculate the frequency of revolution of an electron in the first orbit of an aluminum atom. Given that mass of electron `=9x10^(-31) kg, e= 1.6 xx10^
Correct Answer - `3.25xx10^(18) rev.//sec`
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