Calculate the frequency of revolution of an electron in the first orbit of an aluminum atom. Given that mass of electron `=9x10^(-31) kg, e= 1.6 xx10^(-19) C`, radius of the orbit `=0.2xx10^(-11) m`.
Answered Feb 05, 2023
Correct Answer - `3.25xx10^(18) rev.//sec`
Correct Answer - A Same charge near to each other.
Correct Answer - (b) `z = 48`
Correct Answer - `lambda_(0) = (2h)/(sqrt(2mk) + (k)/(c))`
Correct Answer - `-1.088xx10^(-18)J`
Correct Answer - `1.875 xx10^(7)ms^(-1)`
Correct Answer - `-2.304xx10^(-18) J`
Correct Answer - `4.82xx10^(-12)m, 1.928xx10^(-1) m`
Correct Answer - 1.0211 MeV
(B) (iii), (i), (ii)
Correct option is B) emitted
Install the Bissoy app to consult with a doctor.
Log in to ask questions, provide answers, or leave comments.