Assume that an electron and a position pair is formed from a gamma ray photon having energy 3.0 MeV. Find the total kinetic energy of the positron and

To determine the Q value for this decay, we first need to find the mass of the product nucleus `.^(12)C` in its excited state. In the ground state, `.^(12)C` has...

Correct Answer - A::B::D `A=[(cos alpha,sin alpha,0),(cos beta,sin beta,0),(cos gamma,sin gamma,0)][(cos alpha,cos beta,cos gamma),(sin alpha,sin beta,sin gamma),(0,0,0)]` Clearly, A is symmetric and `|A|=0`, hence, singular and not invertiable. Also, `A A^(T)...

Correct Answer - An electron having `11 eV` kinetic energy.

Correct Answer - 1.008968u

Correct Answer - (a) No (b) `m_(0)=(h^(2)v^(2))/(2c^(2)[hv-2m_(0)c^(2)])`

Correct Answer - D `(d)` We have `betaalpha+gammaalpha+alphabeta=0` `Delta=(1)/(alpha^(3)beta^(3)gamma^(3))|{:(betagamma,gammaalpha,alphabeta),(gammaalpha,alphabeta,betagamma),(alphabeta,betagamma,gammaalpha):}|` `=(1)/(alpha^(3)beta^(3)gamma^(3))|{:(betagamma+gammaalpha+alphabeta,gammaalpha,alphabeta),(gammaalpha+alphabeta+betagamma,alphabeta,betagamma),(alphabeta+betagamma+gammaalpha,betagamma,gammaalpha):}|` [using `C_(1)toC_(1)+C_(2)+C_(3)`] `=(1)/(alpha^(3)beta^(3)gamma^(3))|{:(0,gammaalpha,alphabeta),(0,alphabeta,betagamma),(0,betagamma,gammaalpha):}|=0` [all zero property].

Correct Answer - [10 us by both]

Correct Answer - `[T_(n) = (Q + (1 -m_(a)//m_(c))T)/(1 + m_(n)//m_(c)) = 8.5 MeV]`

Correct Answer - 1.024 MeV

Correct Answer - 1.0211 MeV