The excess pressure inside an air bubble of radius `r` just below the surface of water is `P_(1)`. The excess pressure inside a drop of the same radiu

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The excess pressure inside an air bubble of radius `r` just below the surface of water is `P_(1)`. The excess pressure inside a drop of the same radius just outside the surface is `P_(2)`. If `T` is surface tension then
A. `P_(1)=2P_(2)`
B. `P_(1)=P_(2)`
C. `P_(2)=2P_(1)`
D. `P_(2)=0,P_(1)ne0`


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Salim Ahmed Kawsar

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Correct Answer - B
Excess pressure inside a bubble just below the surface of water `P_(1)=(2T)/(r )`
and excess pressure inside a drop `P_(2) = (2T)/(r ) " "therefore P_(1)=P_(2)`

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