A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. Surface tension of mercury `=0.465Jm^-2`

Monjur Alahi

A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. Surface tension of mercury `=0.465Jm^-2`
A. `23.4muJ`
B. `18.5muJ`
C. `26.8muJ`
D. `16.8muJ`


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Salim Ahmed Kawsar

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Correct Answer - A
Increase in surface energy
`=4piR^(2)T(n^(1//3)-1)=4pi (2xx10^(-3))^(2) (0.465 )(8^(1//3)-1) = 23.4xx10^(-6) J = 23.4 muJ`

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