In an oil drop experiment, the distance between the capacitor plates = 0.076 m, the p.d. between the plates = 5000 V and the radius of drop = `2.75 xx 10^(-6)cm`. The minimum change in velocity with the field `= 5.27 xx 10^(5) cms^(-1)`. If viscosity of air `-1.83 xx 10^(-5)` Ns `m^(-2)`, calculate the charge on the electron.


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Correct Answer - `1.6 xx 10^(-19)` coulomb

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