A Soap bubble has a thickness of 90 nm and its refractive index is `mu" = 1.4"`. What colour does the bubble appear to be at a point on its surface closest to an observer when it is illuminated by white light?
`(1)/(f)=((mu_(i))/(mu_(s))-1) [(1)/(R_(1))-(1)/(R_(2))]`
For concave lens `[(1)/(R_(1))-(1)/(R_(2))]=-ve`
here `=1.25`
`s=1.32`
Then `((mu_(i))/(mu_(s))-1)=-ve`
Then `(1)/(f)rarr(-ve)(-ve)`
Thus it will behave like converging lens.
Correct Answer - D
As volume of the bubble `V=(4)/(3) pi R^(3) implies R = ((3)/(4pi))^(1//3)V^(1//3) implies R^(2) = ((3)/(4pi))^(2//3) V^(2//3) implies R^(2) prop V^(2//3)`
Work done in blowing a soap...
Correct Answer - 1.45
The path difference is `2mu t`.
Now for destructive interface it can be
`2mut=(lambda)/(2)` or `(3lambda)/(2)` or `(5lambda)/(2)` and so on………
`mu=(lambda)/(4 t),(3lambda)/(4 t),(5lambda)/(4 t)……..`
`=(580xx10^(-9))/(4xx0.3xx10^(-6)) ,...