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The binding energy of deuteron is `2.2` MeV and that of `._(2)^(4)He` is `28` MeV. If two deuterons are fused to form one `._(2)^(4)He`, th `n` the en

Monjur Alahi

The binding energy of deuteron is `2.2` MeV and that of `._(2)^(4)He` is `28` MeV. If two deuterons are fused to form one `._(2)^(4)He`, th `n` the energy released is
A. `23.6 MeV`
B. `19.2 MeV`
C. `30.2 MeV`
D. `25.8 MeV`


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1 Answers

Salim Ahmed Kawsar

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Correct Answer - A
`2 "Deuteron rarr ._(2)^(4)He`
`Q = "BE of Product" - "BE of reactant"`
`= [28 MeV - 2(2.2 MeV)]`
`= [28-4.4 ] = 23.6 MeV`

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