Login
Get Advice on Live Video Call
Earn $ Cash $ with
consultations on Bissoy App

The energy of a tungsten atom with a vacancy in L small is `11.3 KaV`. Wavelength of `K_(alpha)` photon for tungsten is `21.3 "pm"`. If a potential di

Monjur Alahi

The energy of a tungsten atom with a vacancy in L small is `11.3 KaV`. Wavelength of `K_(alpha)` photon for tungsten is `21.3 "pm"`. If a potential difference of `62 kV` is applied across the `X`-raystube following characterstic X-rays will be produced.
A. K,L series
B. only `K_(alpha)` & `L` series
C. only L series
D. None of these


0 like 0 dislike
1 views
Share with your friends

1 Answers

Salim Ahmed Kawsar

Call

Correct Answer - C
`DeltaE = (hc)/(lambda) = (1240)/(lambda(nm)) rArr = (1240)/(21.3 xx 10^(-3))`
`E_(2) = 58.21 KeV , DeltaE_(1) = 11.3 KeV, DeltaE = 69.51 KeV`
`DeltaE lt 62 KeV` Therefore only `1`, series will be produced.

0 like 0 dislike
1 views
A nucleus with Z =92 emits the following in a sequence: `alpha,beta^(-),beta^(-),alpha,alpha,alpha,alpha,alpha,beta^(-),beta^(-),alpha,beta^(+),beta^(

Correct Answer - B `8 alpha` have been emitted `4 beta^(-)` have been emitted `2 beta^(+)` have emitted `alpha` reduces atomic number by 2 `beta^(-)` increases atomic number by 1 `beta^(+)`...

2 Answers 2 views
The energy of gamma `(gamma)` ray photon is `E_(gamma)` and that of an X-rays photon is `E_(X)`. If the visible light photon has an energy of `E_(v)`,

Correct Answer - C `E_(gamma) ge 100 keV, E_(X) = 100 eV` to `100 keV`. So, we can say that `E_(y) gt E_(x) gt E_(v)`,

2 Answers 1 views
In a hydrogen atom, a transition takes place from n = 3 to n = 2 orbit. Calculate the wavelength of the emitted photon. Will the photon be visible ? T

The wavelength of the emitted photon is given by `(1)/(lambda)=R((1)/n_(1)^(2)-(1)/(3^(2)))` When the transition takes place n =3 to n=2, then `(1)/(lambda)=(1.097xx10^(7))((1)/(2^(2))-(1)/(3^(3)))` `=1.097xx10^(7)xx(4)/(36)` `:." " lambda=(36)/(1.097xx10^(7)xx5)=6.563xx10^(-7) m` `=6563Å` `lambda` falsl in...

2 Answers 1 views
The energy of an element with a vacancy in K-shell is 35.2 V, in L-shell is 5.25 keV and in M-shell is 0.55 keV higher than the energy of the atom of

It is given that, `E_(K)=35.2keV,E_(L)=5.25keV,E_(M)=0.55 keV` `rArr" " E_(K)-E_(L)=(hc)/(lambda_(K_(A_(alpha))))=hv_(K_(alpha))` `rArr(35.2-5.25)xx10^(3)xx1.6xx10^(-19)=6.6xx10^(-34)v_(K_(alpha))` `rArr" " v_(K_(alpha))=(29.95xx10^(3)xx1.6xx10^(-19))/(6.6xx10^(-34))=7.2xx10^(-34)Hz` Similarly, `E_(K)-E_(M)=hv_(K_(beta))` `rArr" " v_(K_(beta))=((35.2-0.55)xx10^(3)xx1.63xx10^(-19))/(6.6xx10^(-34))=8.4xx10^(18)Hz` Also, `E_(L)-E_(M)=hv_(k_(alpha))` `rArr" " ((5.25-0.55)xx10^(3)xx1.6xx10^(-19))/(6.6xx10^(-34))=1.1xx10^(18)Hz`

2 Answers 1 views
If `A=[alphabetagamma-alpha]` is such that `A^2=I` , then `1+alpha^2+betagamma=0` (b) `1-alpha^2+betagamma=0` (c) `1-alpha^2-betagamma=0` (d) `1+alpha

Correct Answer - A `A^(2) =I` `implies [{:(alpha,beta),(gamma,-alpha):}][{:(alpha,beta),(gamma,-alpha):}]=I` `implies[{:(alpha^(2)+betagamma,alphabeta-betaalpha),(gammaalpha -alphagamma,betagamma +alpha^(2)):}]=I` `implies [{:(alpha^(2) +beta gamma ,0),(0, alpha^(2) +betagamma ):}]=[{:(1,0),(0,1):}]` `alpha^(2) +beta gamma =1 implies 1-alpha^(2) -betagamma =0`

2 Answers 1 views
A hydrogen atom initially in the ground level absorbs a photon and is excited to `n=4` level then the wavelength of photon is

Correct Answer - C Here ,`n_1=1` and `n_2=4` Energy of photon absorbed, `e=-e_2-e_1` `E_n=-(13.6)/n^2eV` Since, `E_2-E_1=-(13.6)/(4)^2-(-(13.6)/((1)^2))` `=-(13.6)/(16)+13.6=(13.6xx15)/(16)eV` `=12.75eV=12.75xx1.6xx10^(-19)J=20.4xx10^(-19)J` `E_2-E_1=(hc)/(lambda)` `therefore lambda =(hc)/(E_2-E_1)=(6.6xx10^(-34)xx3xx10^(8))/(20.4xx10^(10^(-19)))` `=9.70xx10^(-8)m=970xx10^(-10)=970Å`.

2 Answers 2 views
The energy of a photon is given as, `Delta E`/atom `= 3.03 xx 10^(-19)J "atom"^(-1)` then, the wavelength `(lambda)` of the photon is

Correct Answer - C (c) According to formula =, `E=(hc)/(lambda)(v=(c)/(lambda))` Energy E=hv `3.03xx10^(-19)=(hc)/(lambda)` `lambda=(6.63xx10^(-34)xx3.0xx10^(8))/(3.03xx10^(-19))` `=6.56xx10^(-7) m` `=6.56xx10^(-7)xx10^(9)nm` =`6.56xx10^(2) nm` `=656 nm`

2 Answers 1 views
If a variable takes the discrete values `alpha-4`, `alpha -(7)/(2), alpha-(5)/(2), alpha-2,alpha+(1)/(2), alpha-(1)/(2), alpha+5(alpha gt 0)`, then th

Correct Answer - A Arrange the data as follows : `alpha-(7)/(2), alpha-3, alpha-(5)/(2),alpha-2, alpha-(1)/(2),alpha+(1)/(2),alpha+4,alpha+5` Median `=(1)/(2)` [value of 4th item+value of 5th item] `therefore " Median"=(alpha-2+alpha-(1)/(2))/(2)=(2alpha-(5)/(2))/(2)=alpha-(5)/(4)`

2 Answers 1 views
If `A(alpha, beta)=[("cos" alpha,sin alpha,0),(-sin alpha,cos alpha,0),(0,0,e^(beta))]`, then `A(alpha, beta)^(-1)` is equal to

Correct Answer - A We have, `A(alpha, beta)^(-1)=1/e^(beta) [(e^(beta) cos alpha,-e^(beta) sin alpha,0),(e^(beta) sin alpha,e^(beta) cos alpha,0),(0,0,1)]` `=A(-alpha, -beta)`

2 Answers 2 views
A light photon of wavelength `lambda_(0)` is absorbed by an atom of mass m at rest in ground state. The atom is free to move. The atom after absorbing

Correct Answer - `lambda_(0) = (2h)/(sqrt(2mk) + (k)/(c))`

2 Answers 7 views

Log in to ask questions, provide answers, or leave comments.


Login

Install the Bissoy app to consult with a doctor.


Download