The energy of a photon is given as, `Delta E`/atom `= 3.03 xx 10^(-19)J "atom"^(-1)` then, the wavelength `(lambda)` of the photon is

Correct Answer - C `E_(gamma) ge 100 keV, E_(X) = 100 eV` to `100 keV`. So, we can say that `E_(y) gt E_(x) gt E_(v)`,

The wavelength of the emitted photon is given by `(1)/(lambda)=R((1)/n_(1)^(2)-(1)/(3^(2)))` When the transition takes place n =3 to n=2, then `(1)/(lambda)=(1.097xx10^(7))((1)/(2^(2))-(1)/(3^(3)))` `=1.097xx10^(7)xx(4)/(36)` `:." " lambda=(36)/(1.097xx10^(7)xx5)=6.563xx10^(-7) m` `=6563Å` `lambda` falsl in...

Correct Answer - D The de Brogli wavelength `h=(h)/(mv)rArrv=(h)/(mlambda)` Energy of photon `E_(p)=(hc)/(lambda)(since lambda is same)` Energy of Photon Kinetic energy of photon `=(E_(p))/(E_(e))=(hc//lambda)/((1)/(2)1mu^(2))=(2hc)/(lambdamv^(2))` substituting value of V from Eq (i)...

Correct Answer - C Here ,`n_1=1` and `n_2=4` Energy of photon absorbed, `e=-e_2-e_1` `E_n=-(13.6)/n^2eV` Since, `E_2-E_1=-(13.6)/(4)^2-(-(13.6)/((1)^2))` `=-(13.6)/(16)+13.6=(13.6xx15)/(16)eV` `=12.75eV=12.75xx1.6xx10^(-19)J=20.4xx10^(-19)J` `E_2-E_1=(hc)/(lambda)` `therefore lambda =(hc)/(E_2-E_1)=(6.6xx10^(-34)xx3xx10^(8))/(20.4xx10^(10^(-19)))` `=9.70xx10^(-8)m=970xx10^(-10)=970Å`.

Correct Answer - B Using ,`E=E_g=(hc)/lambda` `=(6.6xx10^(-34)xx3xx10^8)/(589xx10^(-9))J` `=(6.6xx10^(-34)xx3xx10^8)/(589xx10^(-9)xx1.6xx10^(-19))`eV =2.1 eV

Let `lambda_(0)` is the threshold wavelength. The work function is `phi = (hc)/(lambda_(0))` Now, by photoelectric equation `ex = (hc)/(lambda) - (hc)/(lambda_(0))` ……(i) `(ex)/(n+1) = (hc)/(nlambda) - (hc)/(lambda_(0))`……..(ii) From (i)...

Correct Answer - C `{:("As",,W=P DeltaV,,Delta V="same is both process"),("As",,P_(B) gtP_(A),,:. DeltaW_(2) gtW_(1)):}`

We have `[(lambda^(2)-2lambda+1,lambda-2),(1-lambda^(2)+3lambda,1-lambda^(2))]=Alambda^(2)+Blambda+C` Putting `lambda=0`, we get `C=[(1,-2),(1,1)]` Putting `lambda=1`, we get `A+B+C=[(0, -1),(3,0)]` ...(1) Putting `lambda=-1`, we get `A-B+C=[(4,-3),(-3,0)]` Subtracting (2) from (1), we get `2B[(0, -1),(3,0)]-[(4,-3),(-3,0)]=[(-4,2),(6,0)]` `:. B=[(-2,...

Correct Answer - `lambda_(0) = (2h)/(sqrt(2mk) + (k)/(c))`

Correct Answer - (a) No (b) `m_(0)=(h^(2)v^(2))/(2c^(2)[hv-2m_(0)c^(2)])`