The energy of gamma `(gamma)` ray photon is `E_(gamma)` and that of an X-rays photon is `E_(X)`. If the visible light photon has an energy of `E_(v)`,

Correct Answer - A (a) As, A+ `delta`=i+e `rArr 30^(@) + 30^(@) = 60^(@)` + e Angle of emergence , e=`60^(@)-60^(@)`=0 `r_(1)=A=30^(@)` `therefore` Refractive index, `mu=(sin i)/(sin r)=sin 60^(@)/(sin 30^(@))=sqrt3=1.732`

Kinetic energy of electron =30 eV Acccording to the question , 10% of this energy is converted to photon which is given by `(10)/(100)xx30=3 kV` `:. " " lambda_("min")("in"Å)=(12375)/(V("in volt"))=(12375)/(3xx10^3)=4.12Å`...

Correct answer is (d) n1 = n3 < n2  Medium A and C in air, therefore, n1 = n3, but glass slab is of higher refractive index. ∴ n1 = n3 < n2

L.H.S.=`|{:(alpha,alpha^(2),beta+gamma),(beta,beta^(2),gamma+alpha),(gamma,gamma^(2),alpha+beta):}|=|{:(alpha,alpha^(2),alpha+beta+gamma),(beta,beta^(2),alpha+beta+gamma),(gamma,gamma^(2),alpha+beta+gamma):}|` `(C_(3)toC_(3)+C_(1))` `=(alpha+beta+gamma)|{:(alpha,alpha^(2),1),(beta,beta^(2),1),(gamma,gamma^(2),1):}|` `(alpha+beta+gamma)|{:(alpha,alpha^(2),1),(beta-alpha,beta^(2)-alpha^(2),0),(gamma-alpha,gamma^(2)-alpha^(2),0):}|` `(R_(2)toR_(2)-R_(1),R_(3)toR_(3)-R_(1))` `(alpha+beta+gamma)(beta-alpha)(gamma-alpha)|{:(alpha,alpha^(2),1),(1,beta-alpha,0),(1,gamma-alpha,0):}|` `=-(alpha-beta)(gamma-alpha)(alpha+beta+gamma)1.|{:(1,beta+alpha),(1,gamma+alpha)` `=-(alpha-beta)(gamma-alpha)(alpha+beta+gamma)(gamma+alpha-beta-alpha)` `=(alpha-beta)(beta-gamma)(gamma-alpha)(alpha+beta+gamma)` =R.H.S.

Correct Answer - B Monoatomic `" "` `n_(1) = 1` Diatomic `n_(2) = 1 gamma_(2) = (7)/(5)` `(n_(1) + n_(2))/(gamma_("mix") - 1) = (n_(1))/(gamma_(1) - 1) + (n_(2))/(gamma_(2) - 1) implies...

Correct Answer - C Here , power of bulb `=100 W` As intensity, `I = ("Power of visible light")/("area")` `= (100 xx 6//100)/(4pi(8)^(2)) = 7.2 xx 10^(-3) W m^(-2)`

Correct Answer - D `lambda_("micro") gt lambda_("infrared") gt lambda_("ultraviolet") gt lambda_("gamma")`

Correct Answer - D The speed of all electromagnetic waves is same in vaccum.

Correct Answer - C The spectral range of visible light is from about 3 eV to 1.8 eV. Therefore the semiconductor used for fabrication of visible LEDs must at least have...

Correct Answer - A::B::D `A=[(cos alpha,sin alpha,0),(cos beta,sin beta,0),(cos gamma,sin gamma,0)][(cos alpha,cos beta,cos gamma),(sin alpha,sin beta,sin gamma),(0,0,0)]` Clearly, A is symmetric and `|A|=0`, hence, singular and not invertiable. Also, `A A^(T)...