The wavelength of `K_(a)` , X-rays for lead isotopes `Pb^(208),Pb^(206),Pb^(204)" are"lambda_(1),lambda_(2)" and"lambda_(3),` resperctively. Then
A. `lambda_(1)=lambda_(2)gtlambda_(3)`
B. `lambda_(1)gtlambda_(2)gtlambda_(3)`
C. `lambda_(1)ltlambda_(2)ltlambda_(3)`
D. `lambda_(2)=sqrt(lambda_(1)lambda_(3))`


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Correct Answer - D
Since, atomic numer are same `lambda_(1)=lambda_(2)=lambda_(3)`
` or " " lambda_(2)=sqrt(lambda_(1)lambda_(3))`

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