Login
Get Advice on Live Video Call
Earn $ Cash $ with
consultations on Bissoy App

Cut off potential for a metal in photoclectric effect for light of wavelength `lambda_(1), lambda_(2)` and `lambda_(3)` is found to be `V_(1),V_(2)` a

Monjur Alahi

Cut off potential for a metal in photoclectric effect for light of wavelength `lambda_(1), lambda_(2)` and `lambda_(3)` is found to be `V_(1),V_(2)` and `V_(3)` volts , If `V_(1),V_(2)` and `V_(3` are in Arithmetic progression then `lambda_(1),lambda_(2)` and `lambda_(3)` will be in
A. Arithmetic Progression
B. Geiometric Progression
C. Harmonic Progression
D. None


0 like 0 dislike
1 views
Share with your friends

1 Answers

Salim Ahmed Kawsar

Call

Correct Answer - C
`eV_(1)=(hc)/lambda_(1) - phi, eV_(2)=(hc)/lambda_(2) - phi, eV_(3)=h_(0)/lambda_(3)-phi`
if `2V_(2)=V_(1)+V_(3) implies 2/lambda_(2)=1/lambda_(1)+1/lambda_(2)`
harmonic progression

0 like 0 dislike
1 views
5. Radha had been using an inexpensive filament-based light bulb which gives off yellow/orange light to lit her room. Now, as she has started earning, she wants to bring home a tubular lamp which involves a two-step process of generation of light and gives off white light after blinking for a few seconds. Identify the lightinper her requirement.

Please, write complete question.

2 Answers 2 views
If `lambda_(Cu)` is the wavelength of `K_(alpha)` X-ray line of copper (atomic number `29`) and `lambda_(Mo)` is the wavelength of the `K_(alpha)`X-ra

Correct Answer - B `sqrt(C/lambda)=a (Z-b)` `b=1 sqrt(lambda_(Cu)/lambda_(Me))=((Z_(Me)-1)/(Z_(Cu)-1))` `lambda_(Cu)/lambda_(Me)=(41/28)^(2)=2.14`

2 Answers 1 views
The wavelength of the short radio waves, microwaves, ultraviolet waves are `lambda_(1),lambda_(2)` and `lambda_(3)`, respectively, Arrange them in dec

Correct Answer - A we know that , (a) Short radio waves i.e., wavelength range `= 1 xx 10^(-1) m` to `1 xx 10^(4) m` (ii) Microwaves wavelength range `= 1...

2 Answers 1 views
The wavelength of `K_(a)` , X-rays for lead isotopes `Pb^(208),Pb^(206),Pb^(204)" are"lambda_(1),lambda_(2)" and"lambda_(3),` resperctively. Then

Correct Answer - D Since, atomic numer are same `lambda_(1)=lambda_(2)=lambda_(3)` ` or " " lambda_(2)=sqrt(lambda_(1)lambda_(3))`

2 Answers 1 views
`lambda_(1)` and `lambda_(2)` are used to illuminated the slits. `beta_(1)` and `beta_(2)` are the corresponding fringe widths. The wavelength `lambda

Correct Answer - A Fringe width `beta prop lambda` As given that `lambda_(1)` wavelength photo electric effect `lamnda_(1) lt lambda_(2)` Hence, `beta_(1) lt beta_(2)`

2 Answers 1 views
When light of wavelength `lambda` is incident on a metal surface, stopping potential is found to be x. When light of wavelength n`lambda` is incident

Let `lambda_(0)` is the threshold wavelength. The work function is `phi = (hc)/(lambda_(0))` Now, by photoelectric equation `ex = (hc)/(lambda) - (hc)/(lambda_(0))` ……(i) `(ex)/(n+1) = (hc)/(nlambda) - (hc)/(lambda_(0))`……..(ii) From (i)...

2 Answers 3 views
The threshold wavelength `(lambda_(0))` of sodium metal is `6500 Å`. If UV light of wavelength `360 Å` is used, what will be kinetic energy of the pho

Correct Answer - 3 The threshold frequency `(v_(0))` corresponding to the wavelength `6500 Å` is `c//lambda_(0)` Therefore, the threshold energy `=hv_(0)hc//lambda_(0)` Substituting for `h, c` and `lambda_(0)` we gwt threshold energy...

2 Answers 2 views
The wavelength of electron waves in two orbits `(lambda_(1) : lambda_(2))`

Correct Answer - A `lambda=(h)/(sqrt(2mKE)), (lambda_(1))/(lambda_(2))=sqrt((KE_(2))/(KE_(1))), (3)/(5)=sqrt((KE_(2))/(KE_(1))),(KE_(1))/(KE_(2))=(25)/(9)`

2 Answers 1 views
An X-ray tube has nickel as target. The wavelength difference between the ka X-ray and the cut-off wavelength of continuous X-ray spectrum is 84 pm. F

Correct Answer - `14.8 kV`

2 Answers 1 views
When radiations of wavelength `lambda_(1), lambda_(2) (= 0.6 lambda_(1)), lambda_(3) (= 4lambda_(2))` and `lambda_(4)` are incident on a metal plate,

Correct Answer - (a) `5 eV` , (b) `n = 6, Z = 3`

2 Answers 1 views

Log in to ask questions, provide answers, or leave comments.


Login

Install the Bissoy app to consult with a doctor.


Download