The wavelength of electron waves in two orbits `(lambda_(1) : lambda_(2))`
A. `25 : 9`
B. `5 : 3`
C. `9 : 25`
D. `3 : 5`
1 Answers
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Two radioactive material `A_(1)` and `A_(2)` have decay constants of 10 `lambda_(0)` and `lambda_(0)`. If initially they have same number of nuclei, t
Correct Answer - A `A_(1) overset(10lambda_(0))rarrX`Initial no. of nuclei `=N_(0)` `A_(2) overset(lambda_(0))rarrY`Initial no. of nuclei=`N_(0)` For `A_(1)` No. of nuclei left undecayed after time `(1)/(9 lambda_(0))=N_(0)e^(-10lambda_(0)xx(1)/(9 lambda_(0)))=N_(0)e^(-(0)/(9))` For `A_(2)` No. of...
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The wavelength of the short radio waves, microwaves, ultraviolet waves are `lambda_(1),lambda_(2)` and `lambda_(3)`, respectively, Arrange them in dec
Correct Answer - A we know that , (a) Short radio waves i.e., wavelength range `= 1 xx 10^(-1) m` to `1 xx 10^(4) m` (ii) Microwaves wavelength range `= 1...
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The wavelength of `K_(a)` , X-rays for lead isotopes `Pb^(208),Pb^(206),Pb^(204)" are"lambda_(1),lambda_(2)" and"lambda_(3),` resperctively. Then
Correct Answer - D Since, atomic numer are same `lambda_(1)=lambda_(2)=lambda_(3)` ` or " " lambda_(2)=sqrt(lambda_(1)lambda_(3))`
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de-Broglie wavelength of an electron in the nth Bohr orbit is `lambda_(n)` and the angular momentum is `J_(n)` then
Correct Answer - A `lambda (h)/(p)=(h)/(mv)` or `" " lambda prop (1)/(v)` `:. " " lambda_(n)prop n rArr J_(n)=n(h)/(2pi) i.e., J_(n) prop n` Hence, `" " lambda_(n)propJ_(n)`
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The solubility of `[Co(NH)_(3))_(4)Cl_(4)]CIO_(4)`____if the `lambda_(Co(NH_(3))_(4)Cl_(2)^(+)=50, lambda_(ClO_(4)^(-)=70` and the measured resistance
Correct Answer - B `lambda_([CO(NH_3)_4Cl_2]ClO_4)^@=lambda_([CO(NH_3)_4Cl_2^(-)])^@ .^(+lambda^@)[ClO_4^(-)]=50+70=120` `lambda_([CO(NH_3)_4Cl_2]ClO_4)=(1000 K)/M` `K=G sigma` =1/33.5x0.20 `lambda_([CO(NH_3)_4Cl_2]ClO_4)=120xx(1000xx0.20)/(33.5xxM)` `M=(1000xx0.20)/(33.5xx120)=49.75` mmol/L
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`lambda_(1)` and `lambda_(2)` are used to illuminated the slits. `beta_(1)` and `beta_(2)` are the corresponding fringe widths. The wavelength `lambda
Correct Answer - A Fringe width `beta prop lambda` As given that `lambda_(1)` wavelength photo electric effect `lamnda_(1) lt lambda_(2)` Hence, `beta_(1) lt beta_(2)`
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Cut off potential for a metal in photoclectric effect for light of wavelength `lambda_(1), lambda_(2)` and `lambda_(3)` is found to be `V_(1),V_(2)` a
Correct Answer - C `eV_(1)=(hc)/lambda_(1) - phi, eV_(2)=(hc)/lambda_(2) - phi, eV_(3)=h_(0)/lambda_(3)-phi` if `2V_(2)=V_(1)+V_(3) implies 2/lambda_(2)=1/lambda_(1)+1/lambda_(2)` harmonic progression
2 Answers 1 views
The threshold wavelength `(lambda_(0))` of sodium metal is `6500 Å`. If UV light of wavelength `360 Å` is used, what will be kinetic energy of the pho
Correct Answer - 3 The threshold frequency `(v_(0))` corresponding to the wavelength `6500 Å` is `c//lambda_(0)` Therefore, the threshold energy `=hv_(0)hc//lambda_(0)` Substituting for `h, c` and `lambda_(0)` we gwt threshold energy...
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When radiations of wavelength `lambda_(1), lambda_(2) (= 0.6 lambda_(1)), lambda_(3) (= 4lambda_(2))` and `lambda_(4)` are incident on a metal plate,
Correct Answer - (a) `5 eV` , (b) `n = 6, Z = 3`
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(a) If the wavelength of the light incident on a photoelectric cell be reduced from `lambda_(1)` to `lambda_(2) Å`, then what will be the change in th
Correct Answer - 2.3 eV, `1.44 xx 10^(-6)` Vm
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