On operating an X-ray tube at 1 kV. X-rays of minimum wavelength `6.22Å` are producd. I fht tube is operated at `10 kV`, then the minimum wavelength of `X`-rays prodcued will be
A. `0.622Å`
B. `6.22Å`
C. `3.11 Å`
D. `62.2 Å`
Kinetic energy of electron =30 eV
Acccording to the question , 10% of this energy is converted to photon which is given by
`(10)/(100)xx30=3 kV`
`:. " " lambda_("min")("in"Å)=(12375)/(V("in volt"))=(12375)/(3xx10^3)=4.12Å`...