Not considering the electronic spin, the degeneracy of the second excited state `(n = 3)` of H atom is 9, while the degeneracy of the second excited state of `H^(-)` is :
A. 3
B. 5
C. 2
D. 4
Correct Answer - C
An excited electronic state of `He_2^+` is more stable towards dissociation than ground state `He_2`. This is because excited state must have more bonding than antibonding electrons.
Correct Answer - A
Ratio of kinetic energy `K_(1)/K_(2)=((Z_(1)//n_(1))^(2))/((Z_(2)//n_(2))^(2))`
Since `n_(1)=n_(2)=2` & `Z_(1)=1`
for `H, Z_(2)=2` for `He^(+) implies K_(1)/K_(2)=1/4`
Correct Answer - A
(A)For `Li^(2+)`, n=6 to n=3
For H, the similar transition is 2 to 1
For `He^+` , the similar transition is 4 to 2
Energy of `4^(th)`...
Correct Answer - D
In ground state , kinetic energy `= 13.6 eV`, Potential energy `= -27.2 eV`
In first excited state, kinetic energy `= 3.4 eV`, Potential energy `= -...
Correct Answer - B
`E_(1) = (hc)/(lambda) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]`
For second excited state to first excited state
`E_(1) = (hc)/(lambda) [1/4 - 1/9] rArr (hc)/(lambda) ((5)/(36))`
For first excited state...
Correct Answer - A
`10= .^(n)C_(2) implies n=5`, then 5 orbits are involved upon coming to second excited state
so `n^(th)` excited state is `6^(th) [2^(nd), 3^(rd), 4^(th), 5^(th), 6^(th)]`
