For the hypothetical reaction,
`A rarr` Products, rate `=-k[A]`
The negative sign used in the rate expression indicate that
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For a hypothetical reaction, `2A+B hArr C +` energy , the activeation energy of forward reaction `(E_(af))` and backward reaction `(E_(ab))` are relat
Correct Answer - D Draw energy profile diagram
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`CH_(3)CH_(2)CH_(2)Cl overset(alc. KOH)rarr B overset(HBr)rarr C overset("Na//ether")rarr D` In the above reaction, the product D is
Correct Answer - C `CH_(3)CH_(2)CH_(2)Cl overset(alc. KOH)rarr CH_(3)CH=CH_(2) overset(HBr)rarr CH_(3)-underset(Br)underset("| ")("C ")H-CH_(3)overset(Na)underset("ether")rarr underset("2,3-Dimethylbutane")(CH_(3)-overset(CH_(3))overset("| ")("C ")H-overset(CH_(3))overset("| ")("C ")H-CH_(3))`
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`CH-=CH overset(H_(g)SO_(4))underset(H_(2)SO_(4))rarr (X) overset(LiAIH_(4))rarr (Y) overset(P_(4)//Br_(2))rarr (Z)` In this sequence of reaction, the
Correct Answer - C `HC-=CHoverset(H_(2)"O"//Hg^(2+))underset(H_(2)SO_(4))rarrH_(3)C-overset(O)overset(||)underset((X))C-H` `overset(LiAlH_(4))rarrH_(3)C-underset((Y))("CH"_(2))-OHoverset(P_(4)//Br_(2))rarrunderset("Ethyl bromide")(C_(2)H_(5)Br)`
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For the reaction A + B `to` products, rate low expression for rate =`k[A][B]^(2)`. If the volume of the vessel is reduced to `1/3` of its original vol
rate = `k[A][B]^(2)` By reducing the volume to `1/3` of its original volume, the concentration of the reactants will become three times. `therefore` rate = `k[3A][3B]^(2)=27k[A][B]^(2)` ltbr. Hence, the reaction...
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For a reaction : `A+B to` Products. The rate law expression is: rate = `k[A]^(1//3).[B]^(2)`. a) What is the order of the reaction? b) What are the un
a) The rate law epression is: Rate(r) = `k[A]^(1//3)[B]^(2)therefore` Order of reaction `=1/3 + 2=2(1/3)` b) Rate constant, k =`("rate")/([A]^(1//3)[B]^(2))` `therefore` Units of rate constant = `(moldm^(-3)s^(-1))/((mol dm^(-3^(1//3))(mol dm^(-3))^(2)))` `=(moldm^(-3))^(1-7//3)s^(-1)=(mol...
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For a reaction A+B `to` Products, the rate law is -Rate = `k[A][B]^(3//2)` Can the reaction be an elementary reaction? Explain.
In an elementary reaction, the number of atoms or ions which are colliding to react is known as molecularity. Had the reaction been of elementary nature (single step reaction) the...
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The rate of reaction: `2NO + Cl_(2) rarr 2NOCl` is given by the rate, equation rate `= k[NO]_(2)[Cl_(2)]`. The value of the rate constant can be incre
Correct Answer - A a) The value of rate constant depends upon temperature and not upon the initial concentration of reactants and products.
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For the hypothetical reaction `2A + B rarr` Products following data obtained: `|{:("Experiment number","Initial conc of (A)" (mol L^(-1)),"Initial con
From expts. (2) and (3) , it is clear that when concentration of A is kept constant and that of B is doubled, the rate increasefour times. This shows that...
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The reaction `A+OH^(-)rarr` Products, obeys rate law expression as : `(-d[A])/(dt)=k[A][OH^(-)]` If initial concentrations of [A] and `[OH^(-)]` are 0
`A" "+ " "OH^(-)" "rarr` Products `t=0 " " 0.002 " "0.3` `k=(2.303)/(30xx(0.002-03))log_(10).(0.3[0.002-(0.002xx1)/(100)])/(0.002[0.3-(0.002xx1)/(100)])` `k=1.12xx10^(-3)"litre" "mol"^(-1)s^(-1)`
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The reaction `Aoverset(k)rarr` Product, is zero order while the reaction `Boverset(k)rarr` Product, is first order reaction. For what intial concentra
Correct Answer - A For zero order reaction, x=kt `:. (a)/(2)=kxxt_(1//2),i.e.,t_(1//2)=(a)/(2k)" ".....(i)` For frist order reaction, `t_(1//2)=(log_(e)2)/(k)" ".....(ii)` From eqs. (i) and (ii), `(a)/(2k)=(log_(e)2)/(k)` `a=log_(e)4M`
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