In a photon-particle collision (sauch as photon-electron collision), which of the following may not be conserved ?

Correct Answer - A Wavelength of electron, `lamda_(e)=(h)/(sqrt(2mE)) and ` proton, `lamda_(p)=(hc)/(E)` `implies lamda_(e)^(2)=(h^(2))/(2mE) or E=(hc)/(lamda_(p))` `therefore lamda_(e)^(2)=(h^(2))/(2m*(hc)/(lamda_(p))) implies lamda_(e)^(2)=(h^(2))/(2mhc)lamda_(p) implies lamda_(e)^(2)proplamda_(p)`

Given, energy of 2 `gamma`- rays 2E = 10.2 BeV `[because overset(0)underset(-1)e+overset(0)underset(+1)e rarr2gamma -" rays "]` `rArr 2(hc)/(lambda)=10.2BeV[becauseE=(hc)/(lambda)]rArr lambda=(2hc)/(10.2BeV)` Here h = ` 6.63 xx 10^(-34) J - S, c...

Correct Answer - B As no torque is exerted the boy.

Correct Answer - A (a) : energy of photon, `E=hv=(hc)/(lamda_(ph))` where `lamda_(ph)` is the wavelength of a photon, `lamda_(ph)=(hc)/(E)` Wavelength of the electron, `lamda_(e)=(h)/(sqrt(2mE))` `:.(lamda_(ph))/(lamda_(e))=(hc)/(E)xx(sqrt(2mE))/(h)=csqrt((2m)/(E))`

Correct Answer - C (c ) : In a photon-particle collision such as photon-electron collision, the total energy and total momentum are conserved. However of photons may not be conserved in...

Correct Answer - D At mean position velocity is maximum i.e., `v_"max" = omega a rArr omega = v_"max"/a =16/4=4` `v=omega sqrt(a^2-y^2) rArr 8sqrt3 = 4sqrt(4^2-y^2)` `rArr 192=16(16-y^2) rArr 12=16-y^2 rArr...

Correct option is: C) \(\frac {26}{31}\). If 1st May is Monday then 8th, 15th, 22nd & 29th May are also Monday. Total Mondays in month of May = 5. Total number of days in month...

Correct Answer - D d) both energy of activation and frequency factor can be calcualted.

Correct Answer - D `Fe^(2+)` ion has six 3d electrons. D-electron in Fe(Z=26)=6 p-electrons in Ne(Z=10)=6 s-electrons in Mg in Mg(Z=12)=6 p-electrons in Cl(Z=17)=11 d is the correct answer