If m is the mass of an electron and c the speed of light, the ratio of the wavelength of a photon of energy E to that of the electron of the same energy is
A. `csqrt((2m)/(E))`
B. `sqrt((2m)/(E))`
C. `sqrt((2m)/(cE))`
D. `sqrt((m)/(E))`
Correct Answer - A
(a) : energy of photon, `E=hv=(hc)/(lamda_(ph))`
where `lamda_(ph)` is the wavelength of a photon, `lamda_(ph)=(hc)/(E)`
Wavelength of the electron, `lamda_(e)=(h)/(sqrt(2mE))`
`:.(lamda_(ph))/(lamda_(e))=(hc)/(E)xx(sqrt(2mE))/(h)=csqrt((2m)/(E))`
Correct Answer - B
(b) : In a photon-particle collision, (such as photon electron collision), the total energy and total momentum are conserved. However, the number of photons may not be...
Correct Answer - B
(b) : Energy of the incident photon, `E=hv=(hc)/(lamda)` For violet light, `lamda=390nm`
`:."Incident photon energy,"=(6.63xx10^(-34)xx3xx10^(8))/(390xx10^(-9))J`
`=5.1xx10^(-19)J=(5.1xx10^(-19))/(1.6xx10^(-19))eV=3.19eV`
Correct Answer - C
Total kinetic energy of products
`=` Total energy released `(P^(2))/(2m) + (P^(2))/(2m)`
= {mass defect) `c^(2)` (where `m = (M)/(2)` given)
`rArr 2(P^(2))/(2m) = [(M + Deltam)...