The wavelength `lamda_(e)` of ann electron and `lamda_(p)` of a photon of same energy E are related by

Correct Answer - A `13.6 z^(2) ((1)/(1^(2))-(1)/(3^(2))) =(hc)/(lambda)` `13.6z^(2) ((1)/(2^(2))-(1)/(4^(2))) = (hc)/(lambda_(1))` On division, `((8)/(9))/((3)/(16)) = (lambda_(1))/(lambda)` `:. lambda_(1) = (128)/(27)lambda`

`lamda_(1), lt lamda_(B) lt lamda_(p).`

`AI_(2)(SO_4)3 hArr 2AI^(3+)+2SO_(4)^(2-)` `v_+=2` तथा `v__=3` `^^_m^oo v_+lamda_+^oo+v__lamda__^oo` `=2(189)3(160)` `=378+480` `=858 Omega^(-1) cm^2 mol^(-1)`

Correct Answer - D Bond energy of O-H bond =109 kcal/mol `therefore`Energy absorbed in the dissociation of 1 mole of water `(H_(2)O)=2xx109=218`kcal `therefore` Energy released in the formation of 1 mole...

Here it is given that, an electron absorbs 2 photons each of frequency v then v = 2v where, v is the frequency of emitted electron. Given, `" "E_(max)=hv-phi_(0)` Now,...

Correct Answer - B `n_(1)lambda_(1)=n_(2)lambda_(2)` `n_(2)=(n_(1)lambda_(1))/(lambda_(2))=(p lambda_(1))/(lambda_(2))`

Correct Answer - B (b) : In a photon-particle collision, (such as photon electron collision), the total energy and total momentum are conserved. However, the number of photons may not be...

Correct Answer - B (b) : Energy of the incident photon, `E=hv=(hc)/(lamda)` For violet light, `lamda=390nm` `:."Incident photon energy,"=(6.63xx10^(-34)xx3xx10^(8))/(390xx10^(-9))J` `=5.1xx10^(-19)J=(5.1xx10^(-19))/(1.6xx10^(-19))eV=3.19eV`

Correct Answer - A (a) : energy of photon, `E=hv=(hc)/(lamda_(ph))` where `lamda_(ph)` is the wavelength of a photon, `lamda_(ph)=(hc)/(E)` Wavelength of the electron, `lamda_(e)=(h)/(sqrt(2mE))` `:.(lamda_(ph))/(lamda_(e))=(hc)/(E)xx(sqrt(2mE))/(h)=csqrt((2m)/(E))`