The average of 5 consecutive odd numbers A, B, C, D and E is 41. What is the product of A and E?

Let the four consecutive numbers in AP be (a - 3d), (a - d), (a + d) and (a + 3d) So, according to the question. a-3d + a - d +...

(b) A + A + 2 + A + 4 + A + 6 = 180 4A + 12 = 180 A = 42. Next four consecutive even numbers are 50 + 52 +...

(a) Out of the given alternatives, 137 × 139 = 19043 Required smaller number = 137

 (a) According to the question,  x + x + 2 + x + 4 + x + 6 + x + 8 = 140  or, 5x + 20 = 140  or, 5x =...

(a) From the given alternatives, 1763 = 43 × 41

(d) Lowest number of set A = 280/5 – 4 = 52  Lowest number of other set = 52 × 2 – 71 = 33   Required sum = 33 + 34...

 (d) Let the five consecutive numbers be x, x+1, x+2, x+3 and x+4 respectively.  Then, according to the question,  x + x + 1 + x + 2 + x + 3...

(a) Assume the third number = x According to question 2 × 280 + x + 178.5 × 2 = 281 × 5 or, 560 + x + 357 = 1405 or, x +...

(e) Let A = x According to the question x + x +1 + x + 2 + x + 3 + x +4 = 5 × 48 5x + 10 = 240 ⇒ 5x...

(e) Third number = 290 – (48.5 × 2) – (53.5 × 2) = 290 – 97 – 107= 86