The product of two consecutive odd numbers is 19043. Which is the smaller number? (a) 137 (b) 131 (c) 133 (d) 129 (e) None of these
Answered Feb 05, 2023
(a) Out of the given alternatives, 137 × 139 = 19043 Required smaller number = 137
Let x be the smaller of the two consecutive odd positive integers. Then, the other integer is x + 2. Since both the integers are smaller than 10, x + 2 <...
(c) From the given alternatives, 112 × 114 = 12768 Larger number = 114
(b) A + A + 2 + A + 4 + A + 6 = 180 4A + 12 = 180 A = 42. Next four consecutive even numbers are 50 + 52 +...
? = 333 × 131 = 43623
(a) According to the question, x + x + 2 + x + 4 + x + 6 + x + 8 = 140 or, 5x + 20 = 140 or, 5x =...
(a) From the given alternatives, 1763 = 43 × 41
(d) Let the smaller number be x x (x + 2) = 5358 x2 + 2x – 5328 = 0 (x + 74) (x – 42) = 0 x = 72
(b) Let the numbers be x and (x + 2) Then, x × (x + 2) = 582168 x 2 + 2x – 582168 = 0 x2 + 764x – 762x – 582168 =...
(d) Let the two numbers be x and (x + 2). Then, x2 + (x + 2)2 = 6500 x2 + x2 + 4x + 4 = 6500 2x2 + 4x – 6496...
(d) The series is + (7)2, + (6)2, + (5)2, + (4)2, + (3)2 The wrong number is 102. It should be 68 + (6)2 = 104
Log in to ask questions, provide answers, or leave comments.
Install the Bissoy app to consult with a doctor.