The average of 5 consecutive numbers A,B,C,D and E is 48. What is the product of A and E ?

 (a) 2162 (b) 2208 (c) 2024 (d) 2300 (e) None of these


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 (d) Let the five consecutive numbers be x, x+1, x+2, x+3 and x+4 respectively.

 Then, according to the question, 

x + x + 1 + x + 2 + x + 3 + x + 4 = 5 × 48

 or 5x +10 = 5 × 48 

or 5 (x + 2) = 5 × 48 

or x + 2 = 48 

or x = 48 - 2 = 46

  A = x = 46

 and E = x + 4 = 46 + 4 = 50 

 A × E = 46 × 50 = 2300

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