The average of 5 consecutive numbers A, B, C, D and E is 48. What is the product of A and E?
(a) 2162 (b) 2208 (c) 2024 (d) 2800 (e) None of these
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The sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and the last term to the product of the middle terms
Let the four consecutive numbers in AP be (a - 3d), (a - d), (a + d) and (a + 3d) So, according to the question. a-3d + a - d +...
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The sum of four consecutive even numbers. A, B, C, and D is 180. What is the sum of the set of next four consecutive even numbers ?
(b) A + A + 2 + A + 4 + A + 6 = 180 4A + 12 = 180 A = 42. Next four consecutive even numbers are 50 + 52 +...
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The sum of a set of five consecutive even numbers is 140. What is the sum of the next set of five consecutive even numbers?
(a) According to the question, x + x + 2 + x + 4 + x + 6 + x + 8 = 140 or, 5x + 20 = 140 or, 5x =...
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The sum of five consecutive even numbers of set A is 280. What is the sum of a different set B of five consecutive
(d) Lowest number of set A = 280/5 – 4 = 52 Lowest number of other set = 52 × 2 – 71 = 33 Required sum = 33 + 34...
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The average of 5 consecutive numbers A,B,C,D and E is 48. What is the product of A and E ?
(d) Let the five consecutive numbers be x, x+1, x+2, x+3 and x+4 respectively. Then, according to the question, x + x + 1 + x + 2 + x + 3...
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The average of five numbers is 281. The average of the first two numbers is 280 and the average of the last two numbers is 178.5.
(a) Assume the third number = x According to question 2 × 280 + x + 178.5 × 2 = 281 × 5 or, 560 + x + 357 = 1405 or, x +...
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The average of 5 consecutive odd numbers A, B, C, D and E is 41. What is the product of A and E?
Difference between two consecutive odd numbers is 2. ∴ If smallest odd number be x. Then next consecutive odd numbers are x+2,x+4,x+6 and x+8.
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The sum of five numbers is 290. The average of the first two numbers is 48.5 and the average of last two numbers is 53.5.
(e) Third number = 290 – (48.5 × 2) – (53.5 × 2) = 290 – 97 – 107= 86
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The average of 5 positive integers is 436. The average of the first two numbers is 344 and the average
(d) Third number = (436 × 5) – (344 × 2 + 554 × 2) = 2180 – 1796 = 384
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The following table gives the total product schedule of labour. Find the corresponding average product and marginal product schedules of labour.
L TPL AP = TP/L MP = TPn -TPn - 1 0 0 0 - 1 15 15 15 2 35 17.5 20 3 50 16.67 15 4 40 10 -10 5 48 9.6 -8
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