AhmedNazir

Call

Option 2 : A and C only

Calculation:

Statement A:

Traditional Method:

Let the two integers be a and b.

It is given that the product of two integers is 500 and their difference is 5, so equation will be

⇒ a × b = 500 ............(i)

⇒ a - b = 5 .................(ii)

We know that

(a + b)2 = (a - b)2 + 4ab

⇒ (a + b)2 = (5)2 + 4 × 500

⇒ (a + b)2 = 25 + 2000

⇒ (a + b)2 = 2025 = 452

⇒ (a + b) = 45 .............(iii)

On solving equation (i) and (iii) we get,

a = 25 and b = 20

Alternate MethodWe can also find the two integers by assuming such two numbers whose product is 500 and difference is 5.

⇒ 500 = 5 × 100        (100 - 5 ≠ 5)

⇒ 500 = 50 × 10        (50 - 10 ≠ 5)

⇒ 500 = 25 × 20        (25 - 20 = 5)

Hence, the numbers are 25 and 20

Statement A is correct.

Statement B:

By Prime Factorization method, the HCF of 108, 288 and 360 is

⇒ 108 = 2 × 2 × 3 × 3 × 3

⇒ 288 = 2 × 2 × 2 × 2 × 2 × 3 × 3

⇒ 360 = 2 × 2 × 2 × 3 × 3 × 5

Here, common prime factors of 108, 288 and 360 = 2 × 2 × 3 × 3 = 36

Statement B is incorrect.

Statement C:

Least Common Multiple(LCM) = The least number which is exactly divisible by each one of the given numbers is called their LCM.

Let a and b are two integers, then their LCM is,

LCM(a, b) = (a × b)/HCF of a and b.

Statement C is correct.

∴ Only statement A and C are correct.