- A and B only
- A and C only
- B and C only
- C only
Option 2 : A and C only
Calculation:
Statement A:
Traditional Method:
Let the two integers be a and b.
It is given that the product of two integers is 500 and their difference is 5, so equation will be
⇒ a × b = 500 ............(i)
⇒ a - b = 5 .................(ii)
We know that
(a + b)2 = (a - b)2 + 4ab
⇒ (a + b)2 = (5)2 + 4 × 500
⇒ (a + b)2 = 25 + 2000
⇒ (a + b)2 = 2025 = 452
⇒ (a + b) = 45 .............(iii)
On solving equation (i) and (iii) we get,
a = 25 and b = 20
Alternate MethodWe can also find the two integers by assuming such two numbers whose product is 500 and difference is 5.
⇒ 500 = 5 × 100 (100 - 5 ≠ 5)
⇒ 500 = 50 × 10 (50 - 10 ≠ 5)
⇒ 500 = 25 × 20 (25 - 20 = 5)
Hence, the numbers are 25 and 20
Statement A is correct.
Statement B:
By Prime Factorization method, the HCF of 108, 288 and 360 is
⇒ 108 = 2 × 2 × 3 × 3 × 3
⇒ 288 = 2 × 2 × 2 × 2 × 2 × 3 × 3
⇒ 360 = 2 × 2 × 2 × 3 × 3 × 5
Here, common prime factors of 108, 288 and 360 = 2 × 2 × 3 × 3 = 36
Statement B is incorrect.
Statement C:
Least Common Multiple(LCM) = The least number which is exactly divisible by each one of the given numbers is called their LCM.
Let a and b are two integers, then their LCM is,
LCM(a, b) = (a × b)/HCF of a and b.
Statement C is correct.
∴ Only statement A and C are correct.