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Option 2 : 2 only

Calculation:

Let us assume the number has y in units place and x in tens place.

So, the number can be written as 10x + y

Now,

if we interchange the digits ⇒ x in units place and y in tens place

The number obtained = 10y + x

As given in the question we can write

    (10x + y) - (10y + x) = 54

⇒ 9x - 9y = 54 = 9(x - y) = 54

⇒ x - y = 6

⇒ x = y + 6

Here y can't be 0 as after interchanging the digits the number formed will not be a 2-digit number. So the possible outcomes are

If y = 1, x = 7 and the numbers are 71 and 17

If y = 2, x = 8 and the numbers are 82 and 28

If y = 3, x = 9 and the numbers are 93 and 39

Statement 1 is incorrect as by knowing the products of digit is not the only way. If their ratios are given then also we can find the numbers.

Statement 2 is correct as the difference of the digits is obtained by the equation x - y = 6.

Hence, option 2 is correct.

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