- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Option 2 : 2 only
Calculation:
Let us assume the number has y in units place and x in tens place.
So, the number can be written as 10x + y
Now,
if we interchange the digits ⇒ x in units place and y in tens place
The number obtained = 10y + x
As given in the question we can write
(10x + y) - (10y + x) = 54
⇒ 9x - 9y = 54 = 9(x - y) = 54
⇒ x - y = 6
⇒ x = y + 6
Here y can't be 0 as after interchanging the digits the number formed will not be a 2-digit number. So the possible outcomes are
If y = 1, x = 7 and the numbers are 71 and 17
If y = 2, x = 8 and the numbers are 82 and 28
If y = 3, x = 9 and the numbers are 93 and 39
Statement 1 is incorrect as by knowing the products of digit is not the only way. If their ratios are given then also we can find the numbers.
Statement 2 is correct as the difference of the digits is obtained by the equation x - y = 6.
Hence, option 2 is correct.