The C.O.P. of a refrigerator working on a reversed Carnot cycle is T₁ / (T₂ - T₁)
where
T₁ = Lowest absolute temperature,
T₂ = Highest absolute temperature
Answer: Option 1
The efficiency of an heat engine is given by \[\mathop \eta \limits^\iota = \frac{{{Q_1} - {Q_2}}}{{{Q_1}}}\]
For heat pump it is given by \[\mathop \eta \limits^\iota = \frac{{{Q_1}}}{{{Q_1}...
Answer: Option 1
Difference in times required by the first man (A) and second man (B) = 3 hours. Also, if ta and tb are the respective times, then
tb -...
Answer: Option 2
The C.O.P. of an absorption type refrigerator is given by [T₃ (T₁ - T₂)]/ [T₁ (T₂ - T₃)]
(where T₁ = Temperature at which the working substance...
