Answer: Option 1
The efficiency of an heat engine is given by \[\mathop \eta \limits^\iota = \frac{{{Q_1} - {Q_2}}}{{{Q_1}}}\]
For heat pump it is given by \[\mathop \eta \limits^\iota = \frac{{{Q_1}}}{{{Q_1}...
Answer: Option 1
The C.O.P. of a refrigerator working on a reversed Carnot cycle is T₁ / (T₂ - T₁)
where
T₁ = Lowest absolute temperature,
T₂ = Highest absolute temperature