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Answer: Option 1

The efficiency of an heat engine is given by \[\mathop \eta \limits^\iota = \frac{{{Q_1} - {Q_2}}}{{{Q_1}}}\] For heat pump it is given by \[\mathop \eta \limits^\iota = \frac{{{Q_1}}}{{{Q_1} - {Q_2}}}\] Where \[{{Q_1}}\] and \[{{Q_2}}\] are given by heat taken and heat given to the thermal reservoirs respectively. \[ \Rightarrow {\left( {\mathop \eta \limits^\iota } \right)_{heat\,\,engine}} = \frac{1}{{{{\left( {\mathop \eta \limits^\iota } \right)}_{heat\,\,pump}}}}\]