Answer: Option 1
The efficiency of an heat engine is given by \[\mathop \eta \limits^\iota = \frac{{{Q_1} - {Q_2}}}{{{Q_1}}}\]
For heat pump it is given by \[\mathop \eta \limits^\iota = \frac{{{Q_1}}}{{{Q_1}...
Answer: Option 1
Fourier's law of heat conduction is k. A. (dT/dx)
where Q = Amount of heat flow through the body in unit time, A = Surface area of heat...
Answer: Option 1
The C.O.P. of a refrigerator working on a reversed Carnot cycle is T₁ / (T₂ - T₁)
where
T₁ = Lowest absolute temperature,
T₂ = Highest absolute temperature
Answer: Option 4
COP of refrigerating system $$ = \frac{{{\text{heat taken from the low temperature reserviour}}}}{{{\text{work supplied}}}}$$
So, we can say there are no units for COP because the heat taken...
Answer: Option 4
Carnot refrigeration cycle has maximum COP since carnot is an ideal cycle consisting of reversiable changes at each and every step and hence no losses.
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