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You designed an antibody against phosphorylated CTD of RNA polymerase II. Then you use a DNA fragment with lac operon and try to immunoprecipitate the RNA pol II. What will be the expected result?

Correct Answer: No RNA pol II will precipitate
Lac operon is a prokaryotic gene not recognized by eukaryotic RNA polymerase. Thus it will not be transcribing. Non-Transcribing RNA pol II doesn’t have phosphorylated residue in CTD, so it can’t be immunoprecipitated with the given antibody.

In a Drosophila polytene chromosome just before molting you add green labelled antibody against unphosphhorylated RNA pol II CTD and red labelled antibody against phosphorylated RNA pol II CTD. These give fluorescence on adding the respective substrates. What will be the colour in gene 74 EF and 75 B?

Consider the following statements regarding DNA replication and choose the correct answer:
1. The very first requirement of DNA synthesis is the presence of a template or plan along which the new strand is to be constructed
2. The second requirement is of a DNA-dependent-DNA polymerase or simply DNA polymerase enzyme
3. A DNA Pol cannot join two free nucleotides; one of them must be anchored by hydrogen bonds to a DNA strand
4. Replication takes place bidirectionally

In an experiment, you are trying to pull down the site where guanyl transferase binds by co-immunoprecipitation. You run a gel and autoradiograph to see a band denoting GSK-RNA pol II (phosphorylated). What will you see when you perform the same experiment with overexpression of GSK in one setup and overexpression of unlabelled GSK-RNA pol II in the other setup?

If you consider a transcribing RNA pol II with a transcript as small as 30 bases, which serine residue in its CTD will be phosphorylated?

The lac operon is found only in prokaryotes and consists of structural genes and a promoter and operator. Which of the following statements explains why we study the lac operon?

Which one of the combinations of the following statements is true about antibody structure?
P. Limited proteolysis of rabbit IgG with the enzyme pepsin generates two antigen-binding regions (Fab) and an Fc fragment.
Q. Limited proteolysis of rabbit IgG with the enzyme papain generates a single bivalent antigen-binding region F(ab')2 and peptide fragments.
R. The Fc fragment of IgG can self-associate and crystallize into a lattice.
S. The F(ab')2 fragment of IgG is composed of both light and heavy chains.

In an experiment you use DNA pol I – Klenow fragment. When all other requisites for replication are added, then what will be the effect on the newly replicated DNA? Consider leading strand only.

While in vitro transcription your RNA pol is stalled at a position due to mistreatment. Which factor could you act to help the RNA pol overcome the stalled stage?

You are given a DNA fragment with a CBD lesion. Which polymerase(s) will you use to replicate this fragment without taking care of the error?

Which factor phosphorylates the serine residues in RNA pol II CTD?