The resistance of a moving coil galvanometer is `5 ohm`. The maximum current it can measure is `0.015A` . To convert it into an ammeter to measure `1.5A`
A. connected `5//99 ohm` in series
B. connected `99//50 ohm` in parallel
C. connected `5//99 ohm` in parallel
D. connected `99//50 ohm` in series


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Correct Answer - 3
`S=(G)/((i)/(i_(g))-1)`