A galvanometer has a resistance `50 Omega` and it shunted by a `0.5Omega` resistor. The fraction of the main current that flows throught the galvanometer is
A. `1//100`
B. `1//101`
C. `1//10`
D. `1//11`
i. When a charge Q flows from the higher potential point to the lower potential point, its potential energy decreases by an amount,
∆U = QV = I∆tV
where I is current...
Given: E = 10 V, r = 3 Ω, I = 0.5 A
To find: i. Resistance of resistor (R)
ii. Terminal voltage of battery (V)
Formula: I = \(\frac{E}{R+r}\)
Calculation: From formula, R = \(\frac{E}{I}-r\)
∴...
\(\omega^3\) = 1
(∵ ω = 11/3 & ω be imaginary (given))
It means ω is a root of equation x3 - 1 = 0.
It is cleared that 1 is also a root of equation x3 -...
