When the current change from `+2A` to `2A` in `0.05` second, an e.m.f. of `8V` is induced in a coil. The coefficient of self-induction of the coil is
A. `0.1H`
B. `0.2H`
C. `0.4H`
D. `0.8H`


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Correct Answer - A
`e=L(di)/(dt)implies8=Lxx((2-(-2)))/(0.05)impliesL=0.1H`

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