Masses `2kg` and `8kg` are `18cm` apart. The point where the gravitational field due to them is zero, is
A. `6 cm` from `8kg` mass
B. `6 cm` from `2 kg` mass
C. `1.8 cm` from `8 kg` mass
D. `9 cm` from each mass
Given: q = 10 µC = 10 × 10-6 C, F = 16 × 10-4 N
To find: Electric field intensity (E)
Formula: E = \(\frac{F}{q}\)
Calculation: From formula,
E = \(\frac{16\times10^{-4}}{10\times10^{-6}}\) = 160 N/C
i. Density of lines of force i.e., the number of lines of force per unit area around a particular point determines the strength of the magnetic field at that point.
ii....
By Universal law of gravitation,
F = \(\frac{Gm_1m_2}{r^2}\)
The force acting between two point masses m1 and m2, is independent of the nature of medium between them. Therefore, Gravitational force acting between two...